// 最大权闭合图
#include
#include
#include
#include
using namespace std;
const int inf = (int) 1e9;
const int maxn = 70 + 10;
struct Edge{
int u ,v, cap, next;
Edge(int u = 0, int v = 0 ,int cap = 0, int next = -1){
this ->u = u, this ->v = v, this ->cap = cap, this ->next = next;
}
};
Edge edge[maxn * maxn];
int dist[maxn], vis[maxn], head[maxn],cur[maxn],cnt_edge;
void init(){
cnt_edge = 0;
memset(head,-1,sizeof(head));
}
void add(int u ,int v,int cap){
edge[cnt_edge] = Edge(u,v,cap,head[u]);
head[u] = cnt_edge ++;
edge[cnt_edge] = Edge(v,u,0,head[v]);
head[v] = cnt_edge ++;
}
bool bfs(int s,int t ,int n){
queue Q;
while(!Q.empty()) Q.pop();
memset(vis,0,sizeof(vis));
for(int i = 0;i <= n; ++ i) dist[i] = inf;
vis[s] = 1, dist[s] = 0, Q.push(s);
while(!Q.empty()){
int now = Q.front();
Q.pop();
vis[now] = 0;
for(int i = head[now]; i != -1;i = edge[i].next){
Edge & e = edge[i];
if(dist[e.v] > dist[now] + 1 && e.cap){
dist[e.v] = dist[now] + 1;
if(!vis[e.v]){
vis[e.v] = 1;
Q.push(e.v);
}
}
}
}
return dist[t] < inf;
}
int dfs(int x, int t,int a){
if(x == t || !a) return a;
int f, flow = 0;
for(int & i = cur[x];- 1 != i;i = edge[i].next){
Edge & e = edge[i];
if(dist[e.v] == dist[x] + 1 && e.cap && (f = dfs(e.v,t,min(a,e.cap)))){
a -= f;
flow += f;
e.cap -= f;
edge[i^1].cap +=f;
if(!a) break;
}
}
return flow;
}
int maxflow(int s,int t,int n){
int flow = 0;
while(bfs(s,t,n)){
for(int i = 0;i <= n;++i){
cur[i] = head[i];
}
flow += dfs(s,t,inf);
}
return flow;
}
int main(){
int cas, T = 1;
scanf("%d",&cas);
while(cas --){
int n ,m;
int sum = 0;
init();
scanf("%d%d",&n,&m);
int s = 0, t = n + m + 1;
for(int i = 1; i<= n; ++ i){
int val;
scanf("%d",&val);
add(s,i,val);
sum += val;
}
for(int i = 1; i<= m; ++ i){
int val;
scanf("%d",&val);
add(i + n , t, val);
}
for(int i = 1; i<= n; ++ i){
int k;
scanf("%d",&k);
while(k --){
int a;
scanf("%d",&a);
add(i,a + n + 1,inf);
}
}
for(int i = 1; i<= m; ++ i)
for(int j = 1; j<= m; ++ j){
bool ok;
scanf("%d",&ok);
if(ok) add(i + n ,j + n ,inf);
}
int ans = sum - maxflow(s,t,t);
printf("Case #%d: %d\n",T++,ans);
}
return 0;
}
最大权闭合图
最新推荐文章于 2025-01-13 22:42:11 发布
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