A. Game with Integers（博弈&数学）

Problem - A - Codeforces

解析：

        如果n+1或者n-1是三个倍数即为First，否则Second

#include<bits/stdc++.h>
using namespace std;
//#define int long long
const int N=2e5+5;
int n;
void solve(){
	scanf("%d",&n);
	if((n-1)%3==0||(n+1)%3==0) puts("First");
	else puts("Second"); 
}
signed main(){
	int t=1;
	scanf("%d",&t);
	while(t--) solve();
	return 0;
}