笔记1000.while(scanf(“%d“,&n) != EOF)

There are multiple cases.
Ease case contains two integer a, b (1 ≤ a,b ≤ 1000).
Output a+b in a single line.
Time Limit Exceeded Answer:

#include<cstdio>
int main()
{
	int a,b,c;
	while(scanf("%d%d",&a,&b))
	{
		c=a+b;
		printf("%d\n",c);
	}
	return 0;
 } 

引用：EOF的意义及用法(while(scanf("%d",&n) != EOF))

AC：

#include<cstdio>
int main()
{

	int a,b,c;
	while(scanf("%d%d",&a,&b)!=EOF)
	{
		c=a+b;
		printf("%d\n",c);
	}
	return 0;
 }