Codeforces805B. 3-palindrome

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本文介绍如何构造一个特定的字符串，该字符串由字符'a'、'b'和'c'组成，长度为n，且不含长度为3的回文子串。同时，要求字符'c'的数量尽可能少。

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In the beginning of the new year Keivan decided to reverse his name. He doesn't like palindromes, so he changed Naviek to Navick.

He is too selfish, so for a given n he wants to obtain a string of n characters, each of which is either 'a', 'b' or 'c', with no palindromes of length 3 appearing in the string as a substring. For example, the strings "abc" and "abca" suit him, while the string "aba" doesn't. He also want the number of letters 'c' in his string to be as little as possible.

Input

The first line contains single integer n (1 ≤ n ≤ 2·105) — the length of the string.

Output

Print the string that satisfies all the constraints.

If there are multiple answers, print any of them.

Examples

input
2

output
aa

input
3

output
bba

Note

A palindrome is a sequence of characters which reads the same backward and forward.

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题目给出一个n，要求构造出一个只含abc的字符串，要求没有长度为3的回文子串且c尽可能少

思路构造aabbaabbaabbaa这样的即可

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <queue>
#include <string>
#include <vector>
using namespace std;
#define inf 0x3f3f3f3f
#define LL long long


int main()
{
    int n;
    scanf("%d",&n);
    int flag=0;
    int cnt=0;
    for(int i=1; i<=n; i++)
    {
        if(flag==0) printf("a");
        else  printf("b");
        cnt++;
        if(cnt==2)
            cnt=0,flag^=1;
    }
    printf("\n");
    return 0;
}