FormAttachment (Control control)的参数必须是属于同一个composite

最新推荐文章于 2021-02-24 11:25:40 发布

原创最新推荐文章于 2021-02-24 11:25:40 发布 · 295 阅读

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本文探讨了在SWT中使用FormLayout和FormData进行组件布局时遇到的问题。具体分析了当一个Text组件试图放置在另一个Composite（包含按钮）左侧时，由于FormAttachment计算方式导致Text组件无法正常显示的原因。

总的Composite使用的是FormLayout，其中上面一个子Composite使用的是GridLayout，三个button所在的Composite命名为buttonComp. 要想设置下面的text在buttonComp的左边，是不可行的。

		Composite comp = new Composite(parent, SWT.BORDER);
		comp.setLayout(new FormLayout());
		
		Composite aboveComp = createAboveComposite(comp);
		
		Text textBelow = new Text(comp, SWT.BORDER);
		textBelow.setText("Below");
		textBelow.setToolTipText("Below tool tip");
		
		FormData aboveCompFormData = new FormData();
		aboveCompFormData.top = new FormAttachment(0);
		aboveCompFormData.left = new FormAttachment(0);
		aboveCompFormData.right = new FormAttachment(100);
		aboveComp.setLayoutData(aboveCompFormData);
		
		FormData textFormData = new FormData();
		textFormData.top = new FormAttachment(aboveComp);
		textFormData.left = new FormAttachment(0);
		textFormData.right = new FormAttachment(buttonComp);
		textBelow.setLayoutData(textFormData);

实际运行的效果是下面的Text不见了。这是因为在FormData.getRightAttachment方法中

FormAttachment getRightAttachment (Control control, int spacing, boolean flushCache) {
	if (cacheRight != null) return cacheRight;
	if (isVisited) return cacheRight = new FormAttachment (0, getWidth (control, flushCache));
	if (right == null) {
		if (left == null) return cacheRight = new FormAttachment (0, getWidth (control, flushCache));
		return cacheRight = getLeftAttachment (control, spacing, flushCache).plus (getWidth (control, flushCache));
	}
	Control rightControl = right.control;
	if (rightControl != null) {
		if (rightControl.isDisposed ()) {
			right.control = rightControl = null;
		} else {
			if (rightControl.getParent () != control.getParent ()) {//must be same parent
				rightControl = null;
			}
		}
	}

计算出来的numerator为0

如果上面的Composite是遗留的类，不能更改。想要实现下面的Text在buttonComp的左边，可以在下面的Composite中建相同的buttonComp, setVisible(false).