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原创 最大值 最小值 平均值
Private Sub Command1_Click() Dim max As Integer, min As Integer, sum As Integer, average As Single Dim x As Integer, i As Integer Randomize max = 10: min = 99 sum = 0 For i = 1 To 20 x = Int(90
2016-06-02 18:03:00
1435
原创 平行四边形
Private Sub Form_Click() Cls Print For n = 1 To 8 Print Tab(n + 20); For m = 1 To 10 Print Spc(1); "*"; Next m Print Next n End Sub
2016-05-26 16:59:51
526
原创 登陆 笔记
登录--Form-frmLogin StartUpPosition=2 账号---Label TextBox-txtUserID 密码---Label TextBox-txtPassword 登录、取消---CommandButton cmdLogin--default:true---ENTER cmdCancel--cancel:true---ESC 字体:大小:小一 所有控
2016-05-19 17:47:34
354
原创 冒泡排序法
Private Sub Command1_Click() Me.FontSize = 30 Dim a(10) As Integer Dim i As Integer For i = 1 To 10 a(i) = 10 + Int(Rnd() * 100) Print a(i); Next i Print Dim p As String Dim j As Int
2016-05-12 18:07:53
275
原创 选择排序法 排列10个随机产生的10~100之间的数
Dim a(1 To 10) As Integer Private Sub Command1_Click() Form_Load End Sub Private Sub Command2_Click() p = "" For i = 1 To 9 For j = i + 1 To 10 If a(i) t = a(i): a(i) = a(j
2016-05-07 18:18:45
2890
原创 10进制向16进制转化
Private Sub Command1_Click() Me.Font.Size = 60 Dim a As Integer Dim b As Integer Dim s As String Dim yushu As Byte a = 1230 b = 16 While a yushu = a Mod b If yushu s
2016-05-07 16:58:48
475
原创 任意255以内的十进制数转化为16进制数
Private Sub Command1_Click() Me.Font.Size = 35 Print shiliujinzhi(255) End Sub Private Function shiliujinzhi(m As Byte) As String Dim n As Byte n = m Const shiliu As Byte = 16 Dim returnS As S
2016-04-28 17:14:02
3912
原创 任意255以内的十进制数向二进制数的转化
Private Sub Command1_Click() Me.Font.Size = 35 Print erjinzhi(230) End Sub Private Function erjinzhi(m As Byte) As String Dim n As Byte n = m Const er As Byte = 2 Dim returnS As String Dim sh
2016-04-28 17:03:23
1860
原创 将十进制数23转化为二进制数
Private Sub Command1_Click() Me.Font.Size = 35 Dim n As Byte n = 23 Const er As Byte = 2 Dim shang As Byte Dim yushu(1 To 5) As Byte i = 5 shang = n \ er yushu(i) = n Mod er While shang i
2016-04-28 16:33:49
3727
原创 3乘1
Dim a As Byte Dim b As String Dim c As Byte b = Mid(Me.Text1.Text, 1, 1) a1 = Int(Val(b)) b = Mid(Me.Text1.Text, 2, 1) a2 = Int(Val(b)) b = Mid(Me.Text1.Text, 3, 1) a3 = Int(Val(b)) b = Me
2016-04-21 17:40:37
348
原创 多乘二 ?
Private Sub Command1_Click() Dim c1 As Integer Dim c2 As Integer Dim a() As Byte Dim b As String Dim changdu As Long, i As Long changdu = Len(Text1.Text) ReDim a(changdu) For i = 1 To changdu
2016-04-21 17:10:36
286
原创 两位数与个位数之和 ?
Private Sub Command1_Click() Me.Font.Size = 70 Dim n1() As Byte, n1Len As Long Dim n2() As Byte, n2Len As Long Dim yushu1 As Byte Dim yushu2 As Byte Dim yushu2 As Byte Dim shang As Byte Dim i
2016-04-14 17:40:12
423
原创 两个个位数之积
Private Sub Command1_Click() Me.Font.Size = 40 Dim n1 As Byte, n1Len As Long Dim n2 As Byte, n2Len As Long Dim yushu As Byte Dim shang As Byte Dim tempresult As Byte n1 = Int(Val(Me.Text1.Text)
2016-04-14 16:59:06
401
原创 1000以内任意十个整数之和
Option Explicit Private Sub Command1_Click() Font.Size = 30 Dim i As Integer Dim a(10) As Integer Dim sum As Integer Randomize For i = 1 To 10 a(i) = Int(Rnd * 10
2016-04-07 16:22:40
505
原创 最后一个
Option Base 1 Private Sub Command1_Click() Font.size = 30 Dim n As Integer Dim size As Integer size = Int(Val(Me.Text1.Text)) size = Int(Val(Me.Text1.Text)) Dim slerdum() As Integer ReDim sler
2016-03-31 17:43:09
272
原创 另一种做法(15个数中最小的数在最后)
Private Sub Command1_Click() Font.Size = 30 Dim n As Integer Dim slerdum(15) As Integer n = 1 While n slerdum(n) = Int(Rnd * 1000) n = n + 1 Wend Dim swap As Integer m = 1 While
2016-03-31 17:21:53
345
原创 15个数中,最后一个为最小的
Private Sub Command1_Click() Font.Size = 30 Dim n As Integer Dim slerdum(15) As Integer n = 1 While n slerdum(n) = Int(Rnd * 1000) n = n + 1 Wend Dim swap As Integer n = 1 While
2016-03-31 17:04:07
400
原创 vb
Private Sub Command1_Click() Font.Size = 30 Dim n As Integer Dim slerdum(15) As Integer n = 1 While n slerdum(n) = Int(Rnd * 1000) n = n + 1 Wend n = 1 While n Print slerdum
2016-03-31 16:39:51
297
原创 vb作业
Private Sub Command1_Click() Font.Size = 30 Dim n As Integer Dim slerdum(15) As Integer n = 1 While n slerdum(n) = Int(Rnd * 1000) n = n + 1 Wend n = 1 While n Print slerdum
2016-03-31 16:30:17
272
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