Ruoyi 若依项目模板创建多级菜单加载失败问题处理以及路由懒加载失败时将组件更换为notfound

Faith-J

已于 2022-05-23 00:36:40 修改

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文章标签： javascript vue.js ruoyi

于 2022-05-23 00:32:46 首次发布

本文链接：https://blog.youkuaiyun.com/JCM_ZZ/article/details/124919311

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本文档介绍了在 Ruoyi 项目中处理多级菜单加载失败和路由懒加载失败的问题。通过过滤并转换后台传来的路由字符串，确保组件正确加载。当路由懒加载失败时，会将组件替换为 notfound 页面，以提供备用显示。代码示例展示了如何实现这一功能。

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`Ruoyi 若依项目模板创建多级菜单加载失败问题处理以及路由懒加载失败时将组件更换为notfound`

src/store/modules/route.js

/* 遍历后台传来的路由字符串，转换为组件对象 */
function filterAsyncRouter(asyncRouterMap, isRewrite = false/* 是否重写服务端数据结构 */) {
  return asyncRouterMap.filter(route => {
    if (isRewrite && route.children) {
      route.children = filterChildren(route.children)
    }
    if (route.component) {
      if (route.component === 'Layout') {
        route.component = Layout
      } else {
        route.component = loadView(route.component)
      }
    }
    if (route.children && route.children.length) {
      route.children = filterAsyncRouter(route.children, isRewrite)
    }
    return true
  })
}
/* 递归扁平化路由结构 */
function filterChildren(childrenMap, parentRoute) {
  var children = []
  childrenMap.forEach((el, index) => {
    if (parentRoute) {
      el.path = parentRoute.path + '/' + el.path
    }
    if (el.children && el.children.length) {
      if (el.component === 'ParentView') {
        el.children.forEach(c => {
          c.path = el.path + '/' + c.path
          if (c.children && c.children.length) {
            children = children.concat(filterChildren(c.children, c))
            return
          }
          children.push(c)
        })
        return
      }
    }
    children = children.concat(el)
  })
  return children
}
/* 路由懒加载失败时，重置为notfound页面 */
export const loadView = (view) => { // 路由懒加载
  return (resolve) => {
    require([`@/views/${view}`], resolve, err => {
      require([`@/views/error/notfound`], resolve)
      console.log(err)
    })
  }
}