LeetCode 7. Reverse Integer

最新推荐文章于 2022-06-06 18:52:41 发布

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本文介绍了一个C++程序，用于翻转一个32位带符号整数的各位数字。示例展示了输入123将输出321，输入-123将输出-321。该程序考虑了32位整数范围限制，当翻转后的整数溢出时返回0。

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Given a 32-bit signed integer, reverse digits of an integer.

Example 1:

Input: 123
Output: 321

Example 2:

Input: -123
Output: -321

Example 3:

Input: 120
Output: 21

Note:
Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231, 231 − 1]. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.

程序：

class Solution {
public:
    int reverse(int x) {
        long p = 0;
        while(x != 0)
        {
            p  = p * 10 + x % 10;
            x /= 10;
        }
        if(p > INT_MAX || p < INT_MIN) 
            return 0;
        else 
            return p;
    }
};