C++ Lambda表达式不能捕获当前作用域的枚举,枚举在C++中也算是个类型,它不是变量,只有变量才可以被捕获,可以捕获另一个Labmda表达式,前者不必为后者传递捕获后者的捕获列表
另外,C++ Lambda表达式不能引用捕获当前方法|函数中的静态变量(是出于什么原因?),但定义一个非静态的引用变量引用那个静态变量,然后把这个引用传引用给Lambda表达式就可以“间接”引用静态变量了,绕过Lambda表达式不能捕获静态变量的障碍,
#include <iostream>
int main(int argc, char *argv[]){
enum myenum{
heihei=1,
haha,
halo
};
int a(3),b(1);
static int c(5);
auto Lambda1=[a,b]()->int{return a+b;};
auto Lambda2=[a,b]()->int{return a-b;};
auto Lambda3=[Lambda1,Lambda2,&c]()->int{return Lambda1()+Lambda2()+c;};
std::cout<<Lambda3()<<"\n";
std::cin>>a;
return 0;
}
> Executing task: /usr/bin/clang++ -std=c++17 -stdlib=libc++ -g /Users/haypin/VScode/cpptest/Lambda.cpp -o /Users/haypin/VScode/cpptest/Lambda <
/Users/haypin/VScode/cpptest/Lambda.cpp:12:36: error: 'c' cannot be captured because it does not have automatic storage
duration
auto Lambda3=[Lambda1,Lambda2,&c]()->int{return Lambda1()+Lambda2()+c;};
^
/Users/haypin/VScode/cpptest/Lambda.cpp:9:16: note: 'c' declared here
static int c(5);
^
1 error generated.
The terminal process "/bin/bash '-c', '/usr/bin/clang++ -std=c++17 -stdlib=libc++ -g /Users/haypin/VScode/cpptest/Lambda.cpp -o /Users/haypin/VScode/cpptest/Lambda'" terminated with exit code: 1.
Terminal will be reused by tasks, press any key to close it.
error: 'c' cannot be captured because it does not have automatic storage
定义一个引用d引用静态变量c,然后传引用给Lambda表达式就可以了,使Lambda表达式“间接引用“了静态变量:
#include <iostream>
int main(int argc, char *argv[]){
enum myenum{
heihei=1,
haha,
halo
};
int a(3),b(1);
static int c(14);
int &d=c;
auto Lambda1=[a,b]()->int{return a+b;};
auto Lambda2=[a,b]()->int{return a-b;};
auto Lambda3=[Lambda1,Lambda2,/*&c*/&d]()->int{return Lambda1()+Lambda2()+d;};
int nRes=Lambda3();
std::cout<<nRes<<"\n";
std::cin>>a;
return 0;
}

.vscode/tasks.json:
{
"version": "2.0.0",
"tasks": [
{
"type": "shell",
"label": "C/C++: clang++ build active file",
"command": "/usr/bin/clang++",
"args": [
"-std=c++17",
"-stdlib=libc++",
"-g",
"${file}",
"-o",
"${fileDirname}/${fileBasenameNoExtension}"
],
"options": {
"cwd": "${workspaceFolder}"
},
"problemMatcher": [
"$gcc"
],
"group": "build"
}
]
}
.vscode/launch.json:
{
// Use IntelliSense to learn about possible attributes.
// Hover to view descriptions of existing attributes.
// For more information, visit: https://go.microsoft.com/fwlink/?linkid=830387
"version": "0.2.0",
"configurations": [
{
"type": "lldb",
"request": "launch",
"name": "Debug",
"program": "${fileDirname}/${fileBasenameNoExtension}",
"args": [],
"cwd": "${workspaceFolder}",
"console":"integratedTerminal",
"preLaunchTask": "C/C++: clang++ build active file",
}
]
}
mac10.15.6上VScode的clang++编译器默认支持的C++版本应该是低于C++11的,编译任务配置tasks.json中如果不给"-std=c++17"和"-stdlib=libc++"参数在编译时会指出auto类型说明符是C++11扩展,并且捕获列表还没编译成功:

参见VSCode官网文档:https://code.visualstudio.com/docs/cpp/config-clang-mac
补充:C++的Lambda表达式的引用列表捕获的变量或常量,是Lambda表达式定义处上溯作用域链名字查找的,在Lambda表达式执行时进行实参->形参传值或直接使用引用。
本文探讨了C++ Lambda表达式不能捕获枚举和静态变量的原理,以及如何通过引用间接引用静态变量。通过实例展示了如何在Lambda中巧妙地处理这些限制。
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