C - We Love MOE Girls
时限:500MS 内存:32768KB 64位IO格式:%I64d
& %I64u问题描述
Chikami Nanako is a girl living in many different parallel worlds. In this problem we talk about one of them.
In this world, Nanako has a special habit. When talking with others, she always ends each sentence with "nanodesu".
There are two situations:
If a sentence ends with "desu", she changes "desu" into "nanodesu", e.g. for "iloveyoudesu", she will say "iloveyounanodesu". Otherwise, she just add "nanodesu" to the end of the original sentence.
Given an original sentence, what will it sound like aften spoken by Nanako?
In this world, Nanako has a special habit. When talking with others, she always ends each sentence with "nanodesu".
There are two situations:
If a sentence ends with "desu", she changes "desu" into "nanodesu", e.g. for "iloveyoudesu", she will say "iloveyounanodesu". Otherwise, she just add "nanodesu" to the end of the original sentence.
Given an original sentence, what will it sound like aften spoken by Nanako?
输入
The first line has a number T (T <= 1000) , indicating the number of test cases.
For each test case, the only line contains a string s, which is the original sentence.
The length of sentence s will not exceed 100, and the sentence contains lowercase letters from a to z only.
For each test case, the only line contains a string s, which is the original sentence.
The length of sentence s will not exceed 100, and the sentence contains lowercase letters from a to z only.
输出
For every case, you should output "Case #t: " at first, without quotes. The t is the case number starting from 1. Then output which Nanako will say.
样例输入
2 ohayougozaimasu daijyoubudesu
样例输出
Case #1: ohayougozaimasunanodesu Case #2: daijyoubunanodesu
分析:字符串小小的处理一下,水题。
CODE:
<span style="font-size:18px;">#include <iostream>
#include <string.h>
#include <algorithm>
#include <cmath>
using namespace std;
int main()
{
int t,cas=0;
cin>>t;
while(t--){
cas++;
char c[105];
memset(c,0,sizeof(c));
cin>>c;
cout<<"Case #"<<cas<<": ";
int len=strlen(c);
if(len<4){
cout<<c;
}
else{
string s;
for(int i=len-4;i<len;i++)
s+=c[i];
if(s=="desu"){
for(int i=0;i<len-4;i++)
cout<<c[i];
s.erase();
}
else
cout<<c;
}
cout<<"nanodesu"<<endl;
}
return 0;
}
</span>