cf 342c

C. Cupboard and Balloons

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

A girl named Xenia has a cupboard that looks like an arc from ahead. The arc is made of a semicircle with radius r (the cupboard's top) and two walls of height h (the cupboard's sides). The cupboard's depth is r, that is, it looks like a rectangle with base r and height h + rfrom the sides. The figure below shows what the cupboard looks like (the front view is on the left, the side view is on the right).

Xenia got lots of balloons for her birthday. The girl hates the mess, so she wants to store the balloons in the cupboard. Luckily, each balloon is a sphere with radius . Help Xenia calculate the maximum number of balloons she can put in her cupboard.

You can say that a balloon is in the cupboard if you can't see any part of the balloon on the left or right view. The balloons in the cupboard can touch each other. It is not allowed to squeeze the balloons or deform them in any way. You can assume that the cupboard's walls are negligibly thin.

Input

The single line contains two integers r, h (1 ≤ r, h ≤ 107).

Output

Print a single integer — the maximum number of balloons Xenia can put in the cupboard.

Sample test(s)

input

1 1

output

3

input

1 2

output

5

input

2 1

output

2

水题。。。在里面放球，首先在矩形部分里面两边并列直接放就行了，关键就判断一下半圆部分能不能放多一个，如果矩形最上面两个超出分界线部分小于r/2肯定可以再放一个，如果大于r/2，先假设放进去一个，判断加上多出的(sqrt(3)/2+1/2)r会不会超出总高度h+r就行了

#include <iostream>
#include <cmath>
using namespace std;

int main()
{
    int h, r;
    while(cin >> r >> h){
        int num = 2*h/r;
        int ans = 0;
        if(num&1){
            ans+=(num-1)+2;
            double h1=(double)num*r;
            h1+=(sqrt(3)+1)*r;
            if(h1<= 2*h+2*r) ans++;
        }
        else{
            ans += num;
            ans++;
        }

        cout << ans <<endl;
    }
    return 0;
}