二叉搜索树最低访问代价问题C语言

  动态规划的算法.

  计算出当前二叉搜索树构造成最优二叉搜索树后的最低访问代价.虽然还没有去写生成最优二叉搜索树的例程,但已经很开心了.毕竟,接触动态规划算法的第三天,写出了这个,很高兴.

  希望,并且相信,最近能相继写出更多的有关动态规划算法的问题,并且最终游刃有余地掌握.

  代码贴出来吧.就不多说了,自觉写得不错哦.从分析问题到写出代码,用了5小时左右吧.

---

/* 10-31-11-02-05-20.23.c -- 第十章第三十一题 */ #include <stdio.h> #include <stdlib.h> #include <string.h> #define INFINITY (~(1 << 31)) #define LENTH (5) #define SIZE (7) typedef double Item ; typedef struct cell { char letter[LENTH] ; double probability ; } Cell ; int main (void) ; void initialize (Cell * const input, const int size) ; double best (const Cell * const input, const int size) ; double summation (const Cell * const input, const int start, const int end) ; int main (void) { Cell input[SIZE] ; int size = SIZE ; initialize (input, size) ; printf ("The result is :%lf./n", best (input, size)) ; return 0 ; } void initialize (Cell * const input, const int size) { strcpy (input[0].letter, "a") ; input[0].probability = 0.22 ; strcpy (input[1].letter, "am") ; input[1].probability = 0.18 ; strcpy (input[2].letter, "and") ; input[2].probability = 0.20 ; strcpy (input[3].letter, "egg") ; input[3].probability = 0.05 ; strcpy (input[4].letter, "if") ; input[4].probability = 0.25 ; strcpy (input[5].letter, "the") ; input[5].probability = 0.02 ; strcpy (input[6].letter, "two") ; input[6].probability = 0.08 ; } double best (const Cell * const input, const int size) { Item * * table ; Item value, sigma ; int left, right, step, k ; int i, j ; if (NULL == input || size <= 0) return INFINITY ; /* Initialize table. */ table = (Item * *) malloc (sizeof (Item *) * size) ; for (i = 0; i < size; i++) { table[i] = (Item *) malloc (sizeof (Item) * size) ; if (NULL == table[i]) { if (0 == i) return INFINITY ; for (j = i - 1; j >= 0; j--) free (table[j]) ; return INFINITY ; } table[i][i] = input[i].probability ; } /* Core. */ for (step = 1; step < size; step++) { for (left = 0; left < size - step; left++) { right = left + step ; sigma = summation (input, left, right) ; table[left][right] = INFINITY ; for (k = left; k <= right; k++) { value = 0.0 ; if (left <= k - 1) value += table[left][k - 1] ; if (k + 1 <= right) value += table[k + 1][right] ; /* Fucking precedence level! */ if ((value += sigma) < table[left][right]) table[left][right] = value ; } } } value = table[left - 1][right] ; free (table) ; return value ; } double summation (const Cell * const input, const int start, const int end) { Item sum = 0.0 ; int i ; for (i = start; i <= end; i++) sum += input[i].probability ; return sum ; }