#include<stdio.h>
int main()
{
int i;
int sum = 0;
int n;
int d;
printf ("输入等差数列的首项,公差以及所求项数(中间以空格为间隔):");
scanf ("%d %d %d",&i,&d,&n);
for (i ;i <= n; i+=d)//i=+2等价于让i+2;2就是这个等差数列的公差
sum = sum + i;
printf ("该以%d为首项%d为公差的等差数列前%d项合为:%d\n",i,d,n,sum);
return 0;
}
C语言等差数列前n项合
最新推荐文章于 2023-08-19 16:19:58 发布