求解3X3矩阵对角线元素之和
#include<stdio.h>
void main() {
int i;
int sum = 0;
int a[3][3] = {1, 2, 3,
2, 2, 3,
3, 2, 3};
for (i = 0; i < 3; i++) {
sum += a[i][i] + a[i][2 - i];
}
printf("对角线元素之和为%d\n", sum);
}
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