POJ 3030 - Nasty Hacks

Description

You are the CEO of Nasty Hacks Inc., a company that creates small pieces of malicious software which teenagers may use to fool their friends. The company has just finished their first product and it is time to sell it. You want to make as much money as possible and consider advertising in order to increase sales. You get an analyst to predict the expected revenue, both with and without advertising. You now want to make a decision as to whether you should advertise or not, given the expected revenues.

Input

The input consists of n cases, and the first line consists of one positive integer giving n. The next n lines each contain 3 integers, r, e and c. The first, r, is the expected revenue if you do not advertise, the second, e, is the expected revenue if you do advertise, and the third, c, is the cost of advertising. You can assume that the input will follow these restrictions: ?10⁶ ≤ r, e ≤ 10⁶ and 0 ≤ c ≤ 10⁶.

输入三个整数，分别是不打广告时的收益、打广告时的收益以及打广告要付出多少钱。

Output

Output one line for each test case: “advertise”, “do not advertise” or “does not matter”, presenting whether it is most profitable to advertise or not, or whether it does not make any difference.

输出“打广告！干他丫的！” or “打个毛线广告！” or “打不打好像没什么区别……”

Sample Input

3
0 100 70
100 130 30
-100 -70 40

Sample Output

advertise
does not matter
do not advertise

Source

Nordic 2006

水题。

#include<stdio.h>
int main()
{
	int r,e,c,n;scanf("%d",&n);
	while(n){
		scanf("%d%d%d",&r,&e,&c);
		if(r>e-c) printf("do not advertise\n");
		else if(r==e-c) printf("does not matter\n");
		else printf("advertise\n");
		n--;
	}
}