Implement atoi to convert a string to an integer.
Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases.
Notes: It is intended for this problem to be specified vaguely (ie, no given input specs). You are responsible to gather all the input requirements up front.
class Solution:
# @return an integer
def atoi(self, str):
INT_MAX = 2147483647; INT_MIN = -2147483648
sum = 0
i = 0
sign = 1
if str == '': return 0
while i < len(str) and str[i].isspace():
i += 1
if i < len(str) and str[i] == '-' :
sign = -1
if i < len(str) and (str[i] == '-' or str[i] == '+') :
i += 1
while i < len(str) and str[i].isdigit():
digit = int(str[i])
if INT_MAX / 10 >= sum :
sum = sum * 10
else :
return INT_MAX if sign == 1 else INT_MIN
if INT_MAX - digit >= sum :
sum = sum + digit
else :
return INT_MAX if sign == 1 else INT_MIN
i += 1
return sign * sum
本文详细解析了atoi函数的实现原理,包括符号处理、数字读取、溢出检查及最终转换过程,旨在帮助开发者理解底层逻辑并正确使用。
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