1100 Mars Numbers (20 分)

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本文介绍了一种特殊的计数方式，火星人使用13进制，将地球上的数字系统与火星的'13进制'对应，包括特殊名称和转换规则。通过实例演示了如何编写程序进行地球和火星数字系统的互译。

1100 Mars Numbers (20 分)

People on Mars count their numbers with base 13:

Zero on Earth is called “tret” on Mars.
The numbers 1 to 12 on Earth is called “jan, feb, mar, apr, may, jun, jly, aug, sep, oct, nov, dec” on Mars, respectively.
For the next higher digit, Mars people name the 12 numbers as “tam, hel, maa, huh, tou, kes, hei, elo, syy, lok, mer, jou”, respectively.

For examples, the number 29 on Earth is called “hel mar” on Mars; and “elo nov” on Mars corresponds to 115 on Earth. In order to help communication between people from these two planets, you are supposed to write a program for mutual translation between Earth and Mars number systems.

Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer N (<100). Then N lines follow, each contains a number in [0, 169), given either in the form of an Earth number, or that of Mars.

Output Specification:

For each number, print in a line the corresponding number in the other language.

Sample Input:

4
29
5
elo nov
tam

Sample Output:

hel mar
may
115
13

大概意思就是，13进制数。

前13个数是tret",“jan”,“feb”,“mar”,“apr”,“may”,“jun”,“jly”,“aug”,“sep”,“oct”,“nov”,"dec这些

后面数字超过13后第一个数是tam，比如，13就是tem，14就是13+1

#include<bits/stdc++.h>
using namespace std;
string a[13] = {"tret","jan","feb","mar","apr","may","jun","jly","aug","sep","oct","nov","dec"};
string b[13] = {"","tam","hel","maa","huh","tou","kes","hei","elo" ,"syy","lok","mer","jou"};
int change(string s)
{
	int num = stoi(s);
	if(num/13)
    {
		cout <<  b[num/13];
		if(num%13)
        {
			cout << " " << a[num%13];
		}
	}else{
		cout << a[num];
	}
}
void earth(string s)
{
	int l = s.length();
	int num = 0;
	if(l==4)
    {
		cout << "0";
		return ;
	}
	else if(l == 3)
    {
		for(int i = 1;i <= 12;i++)
        {
			if(s==a[i])
            {
				cout<<i;
				return ;
			}
			if(s==b[i])
            {
				cout<<i*13;
				return;
			}
		}
	}
    else
    {
		string str1 = s.substr(0,3),str2 = s.substr(4,3);
		for(int i = 1;i<= 12;i++)
        {
			if(str1==b[i]
              ){
				num+=i*13;
			}
			if(str2==a[i])
            {
				num+=i;
			}
		}
		cout << num;
	}
}
int main()
{
	int n;
	cin >> n;
	getchar();
	for(int i = 0;i < n;i++)
    {
		string s;
		getline(cin,s);
		if(isdigit(s[0]))
        {
			change(s);
		}
        else
        {
			earth(s);
		}
		cout<<endl;
	} 
}