Lweb and String(set)

最新推荐文章于 2019-09-28 22:11:01 发布

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本文介绍了一道关于字符串转换并求最长递增子序列(LIS)的问题，通过使用C++实现，具体探讨了如何将字符串中的每个字符映射为自然数，并找到经过这种转换后能得到的最长严格递增子序列。

Lweb and String

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 1301 Accepted Submission(s): 659

Problem Description
Lweb has a string S.

Oneday, he decided to transform this string to a new sequence.

You need help him determine this transformation to get a sequence which has the longest LIS(Strictly Increasing).

You need transform every letter in this string to a new number.

A is the set of letters of S, B is the set of natural numbers.

Every injection f:A→B can be treat as an legal transformation.

For example, a String “aabc”, A={a,b,c}, and you can transform it to “1 1 2 3”, and the LIS of the new sequence is 3.

Now help Lweb, find the longest LIS which you can obtain from S.

LIS: Longest Increasing Subsequence. (https://en.wikipedia.org/wiki/Longest_increasing_subsequence)

Input
The first line of the input contains the only integer T,(1≤T≤20).

Then T lines follow, the i-th line contains a string S only containing the lowercase letters, the length of S will not exceed 105.

Output
For each test case, output a single line “Case #x: y”, where x is the case number, starting from 1. And y is the answer.

Sample Input
2
aabcc
acdeaa

Sample Output
Case #1: 3
Case #2: 4

根据题意，就是寻找共出现了几个不同的元素`
get:
s.begin()
s.end()
s.clear()
s.empty()
s.max_size()
s.size()

#include <iostream>
#include <cstring>
#include <cstdio>
#include <set>
using namespace std;
char m[12121112];
set<char> k;
int main()
{
    int t;
    cin>>t;
    for(int i=1;i<=t;i++)
    {
        cin>>m;
        for(int j=0;m[j];j++)
        {
            k.insert(m[j]);//插入
        }
        cout<<"Case #"<<i<<": "<<k.size()<<endl;//输出个数
        k.clear();
    }
    return 0;
}