URAL1197解题报告

一道水题啊~~~

1197. Lonesome Knight Time limit: 1.0 second Memory limit: 64 MB The statement of this problem is very simple: you are to determine how many squares of the chessboard can be attacked by a knight standing alone on the board. Recall that a knight moves two squares forward (horizontally or vertically in any direction) and then one square sideways (perpedicularly to the first direction). Input The first line contains the number N of test cases, 1 ≤ N ≤ 100. Each of the following N lines contains a test: two characters. The first character is a lowercase English letter from 'a' to 'h' and the second character is an integer from 1 to 8; they specify the rank and file of the square at which the knight is standing. Output Output N lines. Each line should contain the number of the squares of the chessboard that are under attack by the knight. Sample input output 3 a1 d4 g6 2 8 6

这道题又再一次嘲讽了我的英语功底啊%>_<%；

题意大致是一个8*8的棋盘，一个棋子能否分别在水平（或竖直）方向上走1格（或2格），然后在竖直（或水平）方向上走2（或1）格，且棋子不会走到棋盘外，能则计数一次，最后看一共能走几次；

代码如下：

#include<iostream>
#include<cstring>
using namespace std;
int sufa(char i,char j)
{
    int c=0;
    if(i+1<='h')
    {
        if(j+2<='8')c++;
        if(j-2>='1')c++;
    }
    if(i-1>='a')
    {
        if(j+2<='8')c++;
        if(j-2>='1')c++;
    }
    if(j+1<='8')
    {
        if(i+2<='h')c++;
        if(i-2>='a')c++;
    }
    if(j-1>='1')
    {
        if(i+2<='h')c++;
        if(i-2>='a')c++;
    }
    return c;
}
int main()
{
    int a,c,i;
    char b[5],d,e;
    cin>>a;
    while(a--)
    {
        cin>>b;
        d=b[0];e=b[1];
        c=sufa(d,e);
        cout<<c<<endl;
    }
    return 0;
}