309最佳买卖股票时机含冷冻期
class Solution:
def maxProfit(self, prices: List[int]) -> int:
# 0持有 1不持有 2当天卖出 3冷冻
dp = [[0] * 4 for _ in range(len(prices))]
dp[0][0] = -prices[0]
dp[0][1] = 0
dp[0][2] = 0
dp[0][3] = 0
for i in range(1, len(prices)):
dp[i][0] = max(dp[i - 1][0], dp[i - 1][1] - prices[i], dp[i - 1][3] - prices[i])
dp[i][1] = max(dp[i - 1][1], dp[i - 1][3])
dp[i][2] = dp[i - 1][0] + prices[i]
dp[i][3] = dp[i - 1][2]
return max(dp[len(prices) - 1][1], dp[len(prices) - 1][2], dp[len(prices) - 1][3])
714买卖股票的最佳时机含手续费
class Solution:
def maxProfit(self, prices: List[int], fee: int) -> int:
# 0持有 1不持有
dp = [[0] * 2 for _ in range(len(prices))]
dp[0][0] = -prices[0]
dp[0][1] = 0
for i in range(1, len(prices)):
dp[i][0] = max(dp[i - 1][0], dp[i - 1][1] - prices[i])
dp[i][1] = max(dp[i - 1][1], dp[i - 1][0] + prices[i] - fee)
return dp[len(prices) - 1][1]