SQL tree data struct(7): find the minimal cost route



-- find the minimal cost route

create table flights(departure char(20), destination char(20), cost int)
insert flights
select 'Chicago', 'New York', 10 union
select 'Chicago', 'Milwaukee', 20 union
select 'Denver', 'Chicago', 25 union
select 'Seattle', 'Chicago',30 union
select 'Seattle', 'Denver',40 union
select 'Seattle', 'San Francisco', 50 union
select 'Milwaukee', 'Seattle',11 union    -- cycle 1: to the first source
select 'Milwaukee', 'Michigan', 36 union
select 'Milwaukee', 'Denver', 9 -- cycle 2: to the intermediate source

/*
insert into flights select destination, departure, cost from flights

select * from flights
*/

if object_id('mincostroute') is not null
    drop procedure mincostroute
go

create procedure mincostroute(@from char(20), @to char(20))
with encryption
as
declare @depth int, @hasmore int
select @depth = 0, @hasmore = 1

/* can not use table variable, a table-var can not refer : table-var.field */
select top 0 src=replicate('.',20), dst=replicate('.',20), stops=0, route=replicate('.', 4000), ttlcost=0
    into #map from sysfiles1

insert into #map select '', @from, @depth, @from, 0

while @hasmore > 0
begin
    select @depth = @depth + 1

    insert into #map
    select flights.departure, flights.destination, @depth,
        #map.route + '->' + destination, ttlcost+cost
    from #map inner join flights on #map.dst = flights.departure
    where stops = @depth-1 and flights.destination not in (select src from #map)
    set @hasmore = @@rowcount
end

--select * from #map

--select * from #map where dst = @to
select top 1 route=rtrim(route), ttlcost from #map where dst = @to order by ttlcost asc

drop table #map
go

exec mincostroute 'Seattle', 'Michigan'
drop table flights
drop proc mincostroute
go
 
评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值