ZOJ-2240 Run Length Encoding

Run Length Encoding

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Time Limit: 2 Seconds      MemoryLimit: 65536 KB

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Your task is towrite a program that performs a simple form of run-length encoding, asdescribed by the rules below.

Any sequence ofbetween 2 to 9 identical characters is encoded by two characters. The firstcharacter is the length of the sequence, represented by one of thecharacters 2 through 9. The second character is the value of the repeatedcharacter. A sequence of more than 9 identical characters is dealt with byfirst encoding 9 characters, then the remaining ones.

Any sequence ofcharacters that does not contain consecutive repetitions of any characters isrepresented by a 1 characterfollowed by the sequence of characters, terminated with another 1. If a 1 appears as part of the sequence, it is escaped with a 1, thus two 1 characters are output.

InputSpecification

The input consistsof letters (both upper- and lower-case), digits, spaces, and punctuation. Everyline is terminated with a newline character and no other characters appear inthe input.

OutputSpecification

Each line in theinput is encoded separately as described above. The newline at the end of eachline is not encoded, but is passed directly to the output.

Sample Input

AAAAAABCCCC

12344

Sample Output

6A1B14C

11123124

#include <stdio.h>
#include <string.h>

int main()
{
	char str[1000];
	int i, len, j, t;
	char count[3000][2];
	while(gets(str) != NULL) {
		len = strlen(str);
		for(i = 0, t = 0; i < len;) {
			j = i;
			while(j < len && str[i] == str[j] && j-i < 9) {
				j++;
			}
			count[t][0] = str[i];
			count[t++][1] = j-i+'0';
			i = j;
		}
		for(i = 0; i < t;) {
			if(count[i][1] > '1') {
				printf("%c%c", count[i][1], count[i][0]);
				i++;
			} else {
				j = i;
				printf("1");
				while(j < t && count[j][1] == '1') {
					printf("%c", count[j][0]);
					if(count[j][0] == '1') {
						printf("1");
					}
					j++;
				}
				printf("1");
				i = j;
			}
		}
		printf("\n");
	}
	return 0;
}