LeetCode Integer to Roman

Leetcode || Roman to Integer package pack; /* * 从前向后遍历罗马数字,如果某个数比前一个数小,则加上该数。 * 反之,减去前一个数的两倍然后加上该数。 */ class Solution { private int getInteger(char ch) { switch(ch) { case 'I' : return 1; c 阅读详情

原题链接在这里:https://leetcode.com/problems/integer-to-roman/

与Roman to Integer相呼应。采用贪心算法。

之所以需要考虑900,400,90,40这些情况而不考虑800,300,200,80,30,20这些情况是因为:只有左侧加有特罗马字符的才需要添加,右侧加罗马字符可以等下一位。

e.g. num = 8, 加"V",然后剩下3,依次加三个"I"就可以了。

AC Java:

public class Solution {
    public String intToRoman(int num) {
        String str = "";
        if(num<1 || num>3999)
            return str;
        String [] myStrs = {"M", "CM", "D", "CD", "C", "XC", "L", "XL","X", "IX", "V", "IV", "I"};
        int [] myDigits = {1000,900,500,400,100,90,50,40,10,9,5,4,1}; 
        
        for(int i = 0; num>0; i++){
            while(num >= myDigits[i]){
                num -= myDigits[i];
                str += myStrs[i];
            }
        }
        return str;
    }
}


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