People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for Red, the middle 2 digits for Green, and the last 2 digits for Blue. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.
Input Specification:
Each input file contains one test case which occupies a line containing the three decimal color values.
Output Specification:
For each test case you should output the Mars RGB value in the following format: first output #, then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a 0 to its left.
Sample Input:
15 43 71
Sample Output:
#123456
第一次写的,还不够精炼,对于数据理解还不够到位
#include <iostream>
#include <vector>
using namespace std;
char a[13] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C'};
int RGB[3];
int main() {
int R, G, B;
cin >> RGB[0] >> RGB[1] >> RGB[2];
cout << "#";
for (int i = 0; i < 3; ++i) {
vector<char> v;
do {
v.push_back(a[RGB[i] % 13]);
RGB[i] /= 13;
} while (RGB[i]);
if (v.size() == 1)
cout << "0";
for (int j = v.size() - 1; j >= 0; --j) {
cout << v[j];
}
}
}
附上对数据理解后,更精炼的代码
#include <iostream>
using namespace std;
char a[13] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C'};
int main() {
int R, G, B;
cin >> R >> G >> B;
cout << "#";
cout << a[R / 13] << a[R % 13] << a[G / 13] << a[G % 13] << a[B / 13] << a[B % 13];
}
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