Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input
Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.
Output
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input-1000000 9Sample Output
-999,991
#include <cstdio>
#include <cstring>
#include <cctype>
char c[20];
int main() {
int a, b;
scanf("%d %d", &a, &b);
a = a + b;
sprintf(c, "%d", a);
int n = strlen(c),m;
int count = 0;
m = n;
for (int i = n - 1; i >= 0; i--) {
if (isdigit(c[i])) {
count++;
if (count == 3) {
if (i != 0 && isdigit(c[i - 1])) {
count = 0;
for (int j = m - 1; j >= i; j--) {
c[j + 1] = c[j];
}
c[i] = ',';
m++;
}
}
}
}
printf("%s", c);
return 0;
}
本文介绍了一个简单的C语言程序,该程序接收两个整数作为输入,并以标准格式(每三位数字用逗号分隔)输出这两个整数的和。程序通过字符串操作实现了逗号的插入。
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