当边界是j也就是右边划分x不能选q[r]应该是q[l]或者q[(l+r)/2]
目的是防止无限循环;或者无限划分;
如果n分成0和n或者n和0就会无限划分
1(x=q[l]或者q[(l+i)/2])
#include<iostream>
using namespace std;
void quick_sort(int q[], int l, int r)
{
if (l >= r)
return;
int i = l - 1, j = r + 1, x = q[l];
while (i < j)
{
do i++; while (q[i] < x);//在这里还有下一行不能<=或者>=会内存超限
do j--; while (q[j] > x);
if (i < j)
swap(q[i], q[j]);
}
quick_sort(q, l, j);
quick_sort(q, j + 1, r);
}
int main()
{
int n;
cin >> n;
int* q = new int[n];
for (int i = 0; i < n; i++)
cin >> q[i];
quick_sort(q, 0, n - 1);
for (int i = 0; i < n; i++)
cout << q[i];
return 0;
}
另一种
x=(q[(l+r+1)/2]
#include<iostream>
using namespace std;
void quick_sort(int q[], int l, int r)
{
if (l >= r)
return;
int i = l - 1, j = r + 1, x = q[(l+r+1)/2];
while (i < j)
{
do i++; while (q[i] < x);
do j--; while (q[j] > x);
if (i < j)
swap(q[i], q[j]);
}
quick_sort(q, l, i-1);
quick_sort(q, i, r);
}
int main()
{
int n;
cin >> n;
int* q = new int[n];
for (int i = 0; i < n; i++)
cin >> q[i];
quick_sort(q, 0, n - 1);
for (int i = 0; i < n; i++)
cout << q[i];
return 0;
}