C - Networking

C - Networking

Time Limit:1000MS Memory Limit:10000KB 64bit IO Format:%lld & %llu
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Status
Description
You are assigned to design network connections between certain points in a wide area. You are given a set of points in the area, and a set of possible routes for the cables that may connect pairs of points. For each possible route between two points, you are given the length of the cable that is needed to connect the points over that route. Note that there may exist many possible routes between two given points. It is assumed that the given possible routes connect (directly or indirectly) each two points in the area.
Your task is to design the network for the area, so that there is a connection (direct or indirect) between every two points (i.e., all the points are interconnected, but not necessarily by a direct cable), and that the total length of the used cable is minimal.
Input
The input file consists of a number of data sets. Each data set defines one required network. The first line of the set contains two integers: the first defines the number P of the given points, and the second the number R of given routes between the points. The following R lines define the given routes between the points, each giving three integer numbers: the first two numbers identify the points, and the third gives the length of the route. The numbers are separated with white spaces. A data set giving only one number P=0 denotes the end of the input. The data sets are separated with an empty line.
The maximal number of points is 50. The maximal length of a given route is 100. The number of possible routes is unlimited. The nodes are identified with integers between 1 and P (inclusive). The routes between two points i and j may be given as i j or as j i.
Output
For each data set, print one number on a separate line that gives the total length of the cable used for the entire designed network.
Sample Input
1 0

2 3
1 2 37
2 1 17
1 2 68

3 7
1 2 19
2 3 11
3 1 7
1 3 5
2 3 89
3 1 91
1 2 32

5 7
1 2 5
2 3 7
2 4 8
4 5 11
3 5 10
1 5 6
4 2 12

0
Sample Output
0
17
16
26

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1. 题意：给你n个点，m条边，问将这n个点联通的最小花费。（两点直接相连可能有多条边）
2. 思路：问题转化成求最小生成树：用prime或kurskal解决。
3. 失误：只有一点需注意：在存图时要选取两点间最小的边。
4. 代码如下：

---

prime:

#include<cstdio>
#include<cstring>
using namespace std;

#define inf 0x3f3f3f3f
const int MAXN=1e3+10;
int map[MAXN][MAXN],dis[MAXN];
bool vis[MAXN];
int ans;

void prime(int n)
{
    memset(dis,inf,sizeof(dis)); memset(vis,false,sizeof(vis));
    ans=0; dis[1]=0;
    for(int i=1;i<=n;++i)
    {
        int top=inf,k;
        for(int j=1;j<=n;++j)
        {
            if(!vis[j]&&dis[j]<top)
            {
                top=dis[j];
                k=j;
            }
        }
        vis[k]=true; ans+=top;
        for(int j=1;j<=n;++j)
        {
            if(!vis[j]&&map[k][j]<dis[j])
            {
                dis[j]=map[k][j];
            }
        }
    }
}

int main()
{
    int n,m,i,u,v,w;
    while(~scanf("%d",&n),n)
    {
        memset(map,inf,sizeof(map));
        scanf("%d",&m);
        for(i=1;i<=m;++i)
        {
            scanf("%d %d %d",&u,&v,&w);
            if(map[u][v]>w)//两点之间有多条边直接相连时 选取最小边 
            {
                map[u][v]=map[v][u]=w;
            }
        }
        prime(n);
        printf("%d\n",ans);
    }
    return 0;
}