1134 Vertex Cover (25 分)
A vertex cover of a graph is a set of vertices such that each edge of the graph is incident to at least one vertex of the set. Now given a graph with several vertex sets, you are supposed to tell if each of them is a vertex cover or not.
Input Specification:
Each input file contains one test case. For each case, the first line gives two positive integers N and M (both no more than 104), being the total numbers of vertices and the edges, respectively. Then M lines follow, each describes an edge by giving the indices (from 0 to N−1) of the two ends of the edge.
After the graph, a positive integer K (≤ 100) is given, which is the number of queries. Then K lines of queries follow, each in the format:
Nv v[1] v[2]⋯v[Nv]
where Nv is the number of vertices in the set, and v[i]'s are the indices of the vertices.
Output Specification:
For each query, print in a line Yes
if the set is a vertex cover, or No
if not.
Sample Input:
10 11
8 7
6 8
4 5
8 4
8 1
1 2
1 4
9 8
9 1
1 0
2 4
5
4 0 3 8 4
6 6 1 7 5 4 9
3 1 8 4
2 2 8
7 9 8 7 6 5 4 2
Sample Output:
No
Yes
Yes
No
No
code
#pragma warning(disable:4996)
#include <iostream>
#include <vector>
#include <stdio.h>
#include <string>
#include <set>
using namespace std;
int vertice[10005];
int edge[10005][2];
int main() {
int n, m;
cin >> n >> m;
int x, y;
for (int i = 0; i < m; ++i) {
cin >> edge[i][0] >> edge[i][1];
}
int k, num;
cin >> k;
set<int> ss;
while (k--) {
ss.clear();
cin >> num;
while (num--) {
cin >> x;
ss.insert(x);
}
bool f = 1;
for (int i = 0; i < m; ++i) {
if (ss.find(edge[i][0]) == ss.end() && ss.find(edge[i][1]) == ss.end()) {
f = 0; break;
}
}
if (f) cout << "Yes" << endl;
else cout << "No" << endl;
}
system("pause");
return 0;
}