【C++】井字棋

#include<time.h>//时间种子
#include<iostream>
#include<cctype>//判断是否为数字的函数头文件

using namespace std;

int pd=0,j=0;//判断是否继续
char shu[9];//圈圈叉叉

void youxi();//游戏
void shuchu();//输出
void shuru();//输入
void diannao();//电脑人
void panduan();//判断是否圈插成功

int main()
{
 do{
  system("cls");//清屏

pd=0,j=0;//重新赋值判断条件

  for(int i=0;i<9;i++)//赋值
   shu[i]=i+1+'0';//把整型转换成字符型

  youxi();
 }while(pd);//判断是否继续游戏
}

void youxi()//游戏
{
 int i=0;//i表示经过几个回合，j表示返回值，判断是否成功

 do{
  i++;
  shuchu();
  shuru();

  if(i!=5)
  diannao();

  system("cls");//清屏

  if(i>2)//经过3个回合才判断是否成功
   panduan();

  if(j==1)//判断返回值是否成功
   break;
 }while(i<5);//只能经过5个回合，因为5个回合就填了10个空，减少了电脑人的填写

 cout<<"\t\t\t\t"<<shu[0]<<'|'<<shu[1]<<'|'<<shu[2]<<'\n'
  <<"\t\t\t\t"<<"-----\n"
  <<"\t\t\t\t"<<shu[3]<<'|'<<shu[4]<<'|'<<shu[5]<<'\n'
  <<"\t\t\t\t"<<"-----\n"
  <<"\t\t\t\t"<<shu[6]<<'|'<<shu[7]<<'|'<<shu[8]<<'\n'
  <<endl;//输出最后的结果

 cout<<"\t输入1继续，输入0退出：";
 cin>>pd;//输入是否继续游戏

 while(pd!=1&&pd!=0)//判断输入是否正确
 {
   cin.clear();

   char ch;
   cin.get(ch);
  
   while(ch!='\n')
    cin.get(ch);
   cout<<"输入错误！请重新输入：";

   cin>>pd;
 }


}

void shuchu()//输出
{
 cout<<"\t\t\t"<<"欢迎来到胡胡圈圈叉叉游戏！！\n"
  <<"\t\t\t    (o为电脑，*为玩家）\n\n"
  <<endl;

 cout<<"\t\t\t\t"<<shu[0]<<'|'<<shu[1]<<'|'<<shu[2]<<'\n'
  <<"\t\t\t\t"<<"-----\n"
  <<"\t\t\t\t"<<shu[3]<<'|'<<shu[4]<<'|'<<shu[5]<<'\n'
  <<"\t\t\t\t"<<"-----\n"
  <<"\t\t\t\t"<<shu[6]<<'|'<<shu[7]<<'|'<<shu[8]<<'\n'
  <<endl;

 cout<<"\t请输入上图中相应的序号：";
}

void shuru()//输入
{
 int s;
 cin>>s;//用户输入

 do{
  if(s==-1)//判断是否重复输入
  {
   cout<<"错误！已存在！请重新输入：";
   cin>>s;
  }

  while(s>9||s<1)//判断输入是否正确
  {
   cin.clear();

   char ch;
   cin.get(ch);
  
   while(ch!='\n')
    cin.get(ch);
   cout<<"输入错误！请重新输入：";

   cin>>s;
  }

  switch(s)//判断是否重复
  {
  case 1:{if(shu[0]=='*'||shu[0]=='o') s=-1;
      else shu[0]='*';} break;

  case 2:{if(shu[1]=='*'||shu[1]=='o') s=-1;
      else shu[1]='*';} break;

  case 3:{if(shu[2]=='*'||shu[2]=='o') s=-1;
      else shu[2]='*';} break;

  case 4:{if(shu[3]=='*'||shu[3]=='o') s=-1;
      else shu[3]='*';} break;

  case 5:{if(shu[4]=='*'||shu[4]=='o') s=-1;
      else shu[4]='*';} break;

  case 6:{if(shu[5]=='*'||shu[5]=='o') s=-1;
      else shu[5]='*';} break;

  case 7:{if(shu[6]=='*'||shu[6]=='o') s=-1;
      else shu[6]='*';} break;

  case 8:{if(shu[7]=='*'||shu[7]=='o') s=-1;
      else shu[7]='*';} break;

  case 9:{if(shu[8]=='*'||shu[8]=='o') s=-1;
      else shu[8]='*';} break;
  }
 }while(s==-1);//判断是否重复，重复就重新开始
}

void diannao()//电脑人
{
 int h;

 do{
  do{
   srand(time(0));
   h=rand()%10;
  }while(h<1);//生成随机0-9，但判断h不能为0

  switch(h)//判断是否重复
  {
  case 1:{if(shu[0]=='*'||shu[0]=='o') h=-1;
      else shu[0]='o';} break;

  case 2:{if(shu[1]=='*'||shu[1]=='o') h=-1;
      else shu[1]='o';} break;

  case 3:{if(shu[2]=='*'||shu[2]=='o') h=-1;
      else shu[2]='o';} break;

  case 4:{if(shu[3]=='*'||shu[3]=='o') h=-1;
      else shu[3]='o';} break;

  case 5:{if(shu[4]=='*'||shu[4]=='o') h=-1;
      else shu[4]='o';} break;

  case 6:{if(shu[5]=='*'||shu[5]=='o') h=-1;
      else shu[5]='o';} break;

  case 7:{if(shu[6]=='*'||shu[6]=='o') h=-1;
      else shu[6]='o';} break;

  case 8:{if(shu[7]=='*'||shu[7]=='o') h=-1;
      else shu[7]='o';} break;

  case 9:{if(shu[8]=='*'||shu[8]=='o') h=-1;
      else shu[8]='o';} break;
  }
 }while(h==-1);//重复就重新开始
}

void panduan()//判断是否成功
{
 if(shu[0]=='*'&&shu[1]=='*'&&shu[2]=='*'
 ||shu[3]=='*'&&shu[4]=='*'&&shu[5]=='*'
 ||shu[6]=='*'&&shu[7]=='*'&&shu[8]=='*'
 ||shu[0]=='*'&&shu[3]=='*'&&shu[6]=='*'
 ||shu[1]=='*'&&shu[4]=='*'&&shu[7]=='*'
 ||shu[2]=='*'&&shu[5]=='*'&&shu[8]=='*'
 ||shu[0]=='*'&&shu[4]=='*'&&shu[8]=='*'
 ||shu[2]=='*'&&shu[4]=='*'&&shu[6]=='*')
 {cout<<"\t\t\t    恭喜！你赢了！！\n\n";j=1;}//判断是否为玩家赢

 else
  if(shu[0]=='o'&&shu[1]=='o'&&shu[2]=='o'
  ||shu[3]=='o'&&shu[4]=='o'&&shu[5]=='o'
  ||shu[6]=='o'&&shu[7]=='o'&&shu[8]=='o'
  ||shu[0]=='o'&&shu[3]=='o'&&shu[6]=='o'
  ||shu[1]=='o'&&shu[4]=='o'&&shu[7]=='o'
  ||shu[2]=='o'&&shu[5]=='o'&&shu[8]=='o'
  ||shu[0]=='o'&&shu[4]=='o'&&shu[8]=='o'
  ||shu[2]=='o'&&shu[4]=='o'&&shu[6]=='o')
  {cout<<"\t\t\t    不好意思！你输了！！\n\n";j=1;}//判断是否为电脑人赢
}