Codeforces Round #303 A. Toy Cars

最新推荐文章于 2024-07-15 17:55:50 发布

原创最新推荐文章于 2024-07-15 17:55:50 发布 · 357 阅读

0 ·

CC 4.0 BY-SA版权

codeforces 同时被 2 个专栏收录

11 篇文章

订阅专栏

贪心

8 篇文章

订阅专栏

Little Susie与她哥哥一起玩赛车，并通过设置比赛来决定哪辆赛车表现更佳。比赛结果由矩阵A表示，其中每个元素描述了两辆车碰撞后的状态。任务是找出哪些赛车表现优异，即在碰撞中翻滚的赛车。文章详细介绍了如何通过输入矩阵A来确定哪些赛车是表现优异的，并输出这些赛车的数量及其编号。

Little Susie, thanks to her older brother, likes to play with cars. Today she decided to set up a tournament between them. The process of a tournament is described in the next paragraph.

There are n toy cars. Each pair collides. The result of a collision can be one of the following: no car turned over, one car turned over, both cars turned over. A car is good if it turned over in no collision. The results of the collisions are determined by an n × n matrixА: there is a number on the intersection of theі-th row and j-th column that describes the result of the collision of theі-th and the j-th car:

- 1: if this pair of cars never collided. - 1 occurs only on the main diagonal of the matrix.
0: if no car turned over during the collision.
1: if only the i-th car turned over during the collision.
2: if only the j-th car turned over during the collision.
3: if both cars turned over during the collision.

Susie wants to find all the good cars. She quickly determined which cars are good. Can you cope with the task?

Input

The first line contains integer n (1 ≤ n ≤ 100) — the number of cars.

Each of the next n lines contains n space-separated integers that determine matrix A.

It is guaranteed that on the main diagonal there are - 1, and - 1 doesn't appear anywhere else in the matrix.

It is guaranteed that the input is correct, that is, if A_ij = 1, then A_ji = 2, if A_ij = 3, then A_ji = 3, and if A_ij = 0, then A_ji = 0.

Output

Print the number of good cars and in the next line print their space-separated indices in the increasing order.

Sample test(s)

Input

Output

2
1 3

Input

Output

#include <iostream>
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <algorithm>
#include <cmath>
#define LL long long
#define INF 0x3f3f3f3f

using namespace std;

int s[110][110];
bool vis[110];
int a[110];
int main()
{
    //freopen("in.txt","r",stdin);
    int n;
    while(cin>>n)
    {
        memset(vis,false,sizeof(vis));
        int ant = 0;
        for(int i=1; i<=n; i++)
        {
            for(int j=1; j<=n; j++)
            {
                int x;
                cin>>x;
                if(x == 1)
                    vis[i] = true;
                else if(x == 3)
                    vis[i] = true;
            }
        }
        for(int i=1; i<=n; i++)
        {
            if(!vis[i])
            {
                a[ant++] = i;
            }
        }
        printf("%d\n",ant);
        for(int i=0; i<ant; i++)
        {
            cout<<a[i];
            if(i == ant-1)
                cout<<endl;
            else
                cout<<" ";
        }
    }
    return 0;
}