ACboy needs your help again!
**Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 11902 Accepted Submission(s): 5949**
Problem Description
ACboy was kidnapped!!
he miss his mother very much and is very scare now.You can’t image how dark the room he was put into is, so poor ?.
As a smart ACMer, you want to get ACboy out of the monster’s labyrinth.But when you arrive at the gate of the maze, the monste say :" I have heard that you are very clever, but if can’t solve my problems, you will die with ACboy."
The problems of the monster is shown on the wall:
Each problem’s first line is a integer N(the number of commands), and a word “FIFO” or “FILO”.(you are very happy because you know “FIFO” stands for “First In First Out”, and “FILO” means “First In Last Out”).
and the following N lines, each line is “IN M” or “OUT”, (M represent a integer).
and the answer of a problem is a passowrd of a door, so if you want to rescue ACboy, answer the problem carefully!
Input
The input contains multiple test cases.
The first line has one integer,represent the number oftest cases.
And the input of each subproblem are described above.
Output
For each command “OUT”, you should output a integer depend on the word is “FIFO” or “FILO”, or a word “None” if you don’t have any integer.
Sample Input
4
4 FIFO
IN 1
IN 2
OUT
OUT
4 FILO
IN 1
IN 2
OUT
OUT
5 FIFO
IN 1
IN 2
OUT
OUT
OUT
5 FILO
IN 1
IN 2
OUT
IN 3
OUT
Sample Output
1
2
2
1
1
2
None
2
3
Source
Recommend
lcy | We have carefully selected several similar problems for you: 1701 1700 1703 1704 1706
题解
按照题目进行模拟。
代码如下:
#include <iostream>
#include <string>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <cstdio>
#include <stack>
#include <queue>
#define ll long long
using namespace std ;
int main(){
int t ;
cin >> t ;
while (t --){
int n ;
string str ;
cin >> n >> str ;
stack<int> sta_ ;
queue<int> que_ ;
while (n --){
int k ;
string str1 ;
cin >> str1 ;
if (str == "FIFO"){
if (str1 == "IN"){
cin >> k ;
que_.push(k) ;
}else{
if (que_.size() == 0){
cout << "None" << endl ;
}else{
cout << que_.front() << endl ;
que_.pop() ;
}
}
}else{
if (str1 == "IN"){
int k ;
cin >> k ;
sta_.push(k) ;
}else{
if (sta_.size() == 0){
cout << "None" << endl ;
}else{
cout << sta_.top() << endl ;
sta_.pop() ;
}
}
}
}
}
return 0 ;
}
ACboy被困,需解决怪物提出的数据结构问题才能获救。任务涉及FIFO(先进先出)和FILO(先进后出)操作,通过正确执行IN和OUT指令来寻找答案。使用队列和栈实现,确保理解并正确应用数据结构原理。
326

被折叠的 条评论
为什么被折叠?



