第三章总结-优快云博客

本文链接：https://blog.youkuaiyun.com/China_dragon769/article/details/121277502

本文展示了多个C语言编程实例，包括字符和整数的输入输出、条件判断、浮点数处理、格式化输出以及数学运算。通过这些实例，读者可以了解C语言的基本语法和常用函数的使用方法。

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1.#include<stdio.h>
int main()
{
    char a, b, c;
    scanf_s("%3c%3c%3c*3c%c", &a, &b, &c);
    printf("a=%3c,b=%c,c=%c\n", a, b, c);
    return 0;
2.int man(int x, int y)
{   int z;
    if (x > y)
        z = x;
    else
        z = y;
    return z;
}
3.# include<stdio.h>
int main()
{
    int a = 1,b = 2, c = 3;
    printf("a=%d,b=%d,c=%d",a,b,c);
    return 0;
}
4.# include<stdio.h>
int main()
{
    int a = 123;
    long int b = 32770
        printf("a=%d,b=%ld\n",a,b);
        printf("a=%o,b=%lo\n",a,b);
        printf("a=%#x,b=%ld\n", a + b, b);
        printf("a=%d,b=%d\n",a);
        printf("a+b=%ld\n",a+b,b);
        printf("输出结束\n");
    return 0;
}
5.# include<stdio.h>
int main()
{
    int a, b;
    long int c;
    scanf_s("%d%d%ld",&a,&b,&c);
    printf("a=%d,b=%d,c=%d",a,b,c);
    return 0;
}
6.# include<stdio.h>
int main()
{
    int a, b, c, d;
    scanf_s("%2d%3d%*d,%d%d", &a, &b, &c, &d);
    printf("a=%d,b=%d,c=%d,d=%d",a,b,c,d);
    printf("a = % 4d, b = % -4d, c = % -4d, d = % 4d",a,b,c,d);
    printf("a=%+4d,b=%+4d,c=%+4d,d=%+4d\n",a,b,c,d);
    return 0;
}
7.# include<stdio.h>
int main()
{
    float f;
    double d;
    scanf_s("%f%f",&f,&d);
    printf("%f=%f,d=%f\n",f,d);
    printf("f=%e,d=%e\n",f,d);
    printf("f=%4,2f,d=%,3f\n",f,d);
    return 0;
}
8.# include<stdio.h>
int main()
{
    char a, b, c;
    scanf_s("%c%c%c", &a, &b, &c);
    printf("a=%3c,b=%c,c=%c\n", a, b, c);
    return 0;
}
9.# include<stdio.h>
int main()
{
    char ch;
    ch = getchar();
    putchar(ch);
    return 0;
}
10.# include<stdio.h>
# include<math.h>
# define PI 3.14
int main()
{
    float r, v;
    printf("输入半径 r;");
    scanf_s("%f",&r);
    v = 4.0 / 3 * PI * pow(r, 3);
    return 0;
}
11.# include<stdio.h>
# include<math.h>
# define PI 3.14
int main()
{
    float a, b, c, x1, x2, p, q;
    printf("请输出三个系数;");
    scanf_s("a=%f,b=%f,c=%f",&a,&b,&c);
    p = -b / (2 * a);
    q = sqrt(b * b - 4 * a * c) / (2 * a);
    x1 = p + q;
    x2 = p - q;
    printf("x1=%5,2f\nx2=%5,2f\n",a,b,c);
    return 0;
}