1058 A+B in Hogwarts (20 分)

1058 A+B in Hogwarts (20 分)
If you are a fan of Harry Potter, you would know the world of magic has its own currency system – as Hagrid explained it to Harry, “Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it’s easy enough.” Your job is to write a program to compute A+B where A and B are given in the standard form of Galleon.Sickle.Knut (Galleon is an integer in [0,10
7
], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:
3.2.1 10.16.27
Sample Output:
14.1.28

#include<iostream>
using namespace std;
struct {
	long Galleon;
	int Sickle;
	int Knut;
}money[3];
int main() {
	long sum;
	scanf("%ld.%d.%d", &money[0].Galleon, &money[0].Sickle, &money[0].Knut);
	scanf("%ld.%d.%d", &money[1].Galleon, &money[1].Sickle, &money[1].Knut);
	sum = (money[0].Galleon + money[1].Galleon) * 493 + (money[0].Sickle + money[1].Sickle) * 29 + (money[0].Knut + money[1].Knut);
	money[2].Galleon = sum / 493;
	money[2].Sickle = (sum - money[2].Galleon * 493) / 29;
	money[2].Knut = sum - money[2].Galleon * 493 - money[2].Sickle * 29;
	cout << money[2].Galleon << "." << money[2].Sickle << "." << money[2].Knut;
	return 0;
}