# 只完成了前两个任务
uppercase = [x for x in "QWERTYUIOPASDFGHJKLZXCVBNM"]
lowercase = [x for x in "qwertyuiopasdfghjklzxcvbnm"]
n = int(input())
flag = [1] * n
for i in range(n):
left, right = input().split("=")
left = [x for x in left]
right = [x for x in right]
for x in left:
if x in uppercase or x in lowercase:
if x not in right or left.count(x) != right.count(x):
flag[i] = 0
for x in flag:
if x == 1:
print("Y")
else:
print("N")
CCF 201912-3 Python 20分
最新推荐文章于 2025-12-16 10:44:31 发布
本文介绍了一个简单的Python程序,用于检查输入的字符串左侧是否能在右侧找到完全相同的字符及其出现次数,通过对比左右两侧的字母,判断其是否相等。
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