Java思维题

题目： 100匹马100袋粮食大马驮三袋小马驮两袋，两个小马崽驮一袋，问大马小马小马崽各多少匹？  java代码如何实现？


暴力穷举法：

public class HowManyHorses {

    public static void main(String[] args) {

        final int HORSE_NUMBER = 100;

        final int FOOD_NUMBER = 100;

        for (int bigHorseNumber = 0; bigHorseNumber <= HORSE_NUMBER; bigHorseNumber++) {

            for (int smallHorseNumber = 0; smallHorseNumber <= HORSE_NUMBER; smallHorseNumber++) {

                for (int ponyNumber = 0; ponyNumber <= HORSE_NUMBER; ponyNumber++) {

                    if (bigHorseNumber + smallHorseNumber + ponyNumber == HORSE_NUMBER &&

                        ponyNumber % 2 == 0 &&

                        bigHorseNumber * 3 + smallHorseNumber * 2 + ponyNumber / 2 == FOOD_NUMBER) {

                        System.out.println(bigHorseNumber + " " + smallHorseNumber + " " + ponyNumber);

                    }

                }

            }

        }

    }

}

最简单的问题，最暴利的方法---减去一层循环

public class HowManyHorse {
    public static void main(String[] args) {
        final int HORSE_NUMBER = 100;
        final int FOOD_NUMBER = 100;
        int ponyhorseNumber = 0;
        for (int bigHorseNumber = 0; bigHorseNumber <= HORSE_NUMBER/2; bigHorseNumber++) {
            for (int smallHorseNumber = 0; smallHorseNumber <= HORSE_NUMBER; smallHorseNumber++) {
                    ponyhorseNumber = HORSE_NUMBER-bigHorseNumber-smallHorseNumber;
                    if (
                        ponyhorseNumber % 2 == 0 &&
                        bigHorseNumber * 3 + smallHorseNumber * 2 +ponyhorseNumber / 2 == FOOD_NUMBER) {
                        System.out.println(bigHorseNumber + " " + smallHorseNumber + " " + ponyhorseNumber);
                    
                }
            }
        }
    }
}