PAT a1123

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目的:构建AVL树,然后判断是否是完全二叉树

输入:

一串节点序列

输出:

层序序列

以及判断是否是满二叉树 

#include<stdio.h>
#include<algorithm>
#include<queue>

using namespace std;

struct node{
    int val,height;
    node* left,*right;
};

node* newnode(int v)
{
    node* now = new node;
    now->height = 1;
    now->val = v;
    now->left = NULL;
    now->right= NULL;

    return now;
}
int getheight(node* root)
{
    if(root==NULL) return 0;
    return root->height;
}
int getbalancefactor(node* root)
{
    //获得左右子树的高度差
    return getheight(root->left)-getheight(root->right);
}
void updateheight(node* root)
{
    root->height = max(getheight(root->left),getheight(root->right))+1;//要是和getheight互换,那么每次查询高度差都要计算,可能会超时。更新计算
}
void L(node* &root)
{
    node* temp = root->right;
    root->right = temp->left;
    temp->left = root;
    updateheight(root);
    updateheight(temp);
    root = temp;
}
void R(node* &root)
{
    node* temp = root->left;
    root->left = temp->right;
    temp->right= root;
    updateheight(root);
    updateheight(temp);
    root = temp;
}
void insert(node* &root,int x)
{
    if(root==NULL)
    {
        root = newnode(x);
        return;
    }

    if(x < root->val)
    {
        insert(root->left,x);
        updateheight(root);
        if(getbalancefactor(root)==2)
        {
            if(getbalancefactor(root->left)==1)
            {
                R(root);
            }else
            {
                L(root->left);
                R(root);
            }
        }
    }else{
        insert(root->right,x);
        updateheight(root);
        if(getbalancefactor(root)==-2)
        {
            if(getbalancefactor(root->right)==-1)
            {
                L(root);
            }else
            {
                R(root->right);
                L(root);
            }
        }
    }
}
bool BFS(node* root)
{
    bool flag = true;
    int tag = 0;
    queue<node*> q;
    q.push(root);
    while(!q.empty())
    {
        node* top = q.front();
        printf("%d",top->val);
        q.pop();
        if(top->left!=NULL)
        {
            q.push(top->left);
            if(tag==1)
            {
                flag = false;
            }
        }else
        {
            if(tag==0)
            {
                tag=1;
            }
        }
        if(top->right!=NULL)
        {
            q.push(top->right);
            if(tag==1)
            {
                flag = false;
            }
        }else
        {
            if(tag==0)
            {
                tag=1;
            }
        }
        if(!q.empty())
        {
            printf(" ");
        }else
        {
            printf("\n");
        }
    }
    return flag;
}
int main()
{
    int N;
    scanf("%d",&N);

    node* root = NULL;

    for(int i=0;i<N;i++)
    {
        int x;
        scanf("%d",&x);
        insert(root,x);
    }
    if(BFS(root))
    {
        printf("YES\n");
    }else
    {
        printf("NO\n");
    }
    return 0;
}

反思:忘记了AVL怎么建树了。

华为OD机试真题 新系统【Skill执行链完整性检测】 华为OD机试 新系统真题【Skill执行链完整性检测】,提供C语言、Java、C++、Python、Go、JavaScript源码实现,并提供完整思路讲解,以及在线OJ模拟做题。华为OD机试真题【Skill执行链完整性检测】 阅读详情

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PAT(A) 1123. Is It a Complete AVL Tree (30)

原题目: 原题链接:https://www.patest.cn/contests/pat-a-practise/1123 1123. Is It a Complete AVL Tree (30) An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the...

萧易桥的博客 384

PAT A1123. Is It a Complete AVL Tree

1123. Is It a Complete AVL Tree (30) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue An AVL tree is a self-balancing binary search tr

u014226072的专栏 397

PAT A1123 Is It a Complete AVL Tree

PAT A1123 Is It a Complete AVL Tree 思路 1: 建树 层序遍历,初始起点的id即为1,每次将当前出队节点now的id在has表里标记上,now的左孩子id为:2now->id,右孩子id:2now->id+1 遍历has表,如果1~n有点未被标记:不是完全二叉树,否则YES:如果是完全二叉树,按id记录下来的节点,一定是从1到n连续的 #i...

qq_42347617的博客 216

PAT A 1120 1121 1122 1123

1120 STL 题目大意: 若两个数的数位上的数字加起来相等,则为朋友数。 例如:1+2+3 = 5+1 = 6,因此123和51是朋友数。给你一些数字,计算不同朋友数的值。思路: 只需要计算不同朋友数的值,因此每次先计算一下值,然后插入set就好啦。 #include&lt;iostream&gt; #include&lt;set&gt; using namespace std; //...

大美mixer的博客 220

PAT 1123 Is It a Complete AVL Tree

原题链接:1123 Is It a Complete AVL Tree (30分) 关键词:AVL、层序遍历 参考的柳神的博客:1123. Is It a Complete AVL Tree (30)-PAT甲级真题 题目大意: 给出一些整数序列用于插入构造AVL,让你输出AVL树的层序遍历,并判断这棵树是不是完全二叉树。

cwtnice的博客 159

PAT_A1123#Is It a Complete AVL Tree

Source: PAT A1123Is It a Complete AVL Tree(30分) Description: An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child subtrees of any node differ by...

weixin_34174132的博客 146

PAT_A_1123 Is It a Complete AVL Tree

题意:构造一颗平衡二叉树,求AVL树的层序遍历并判断是否是一颗完全二叉树 思路:考察构造AVL树及判断是否是完全二叉树,构造平衡二叉树前面一个题目有涉及,PAT甲级1066,在层次遍历的时候发现第一个左右孩子为空的时候置标志位为1,然后判断后序还是否存在孩子节点不为空的情况 代码: #include<iostream> #include<queue> #includ...

qq_42152681的博客 154

pat甲级1123Is It a Complete AVL Tree (30分)

pat甲级1123Is It a Complete AVL Tree (30分) 模板题;代码较长,半小时敲完。。。。。。打字太慢 文章目录pat甲级1123Is It a Complete AVL Tree (30分)1.AVL插入结点模板2.层序遍历模板3.主函数 1.AVL插入结点模板 struct node { int data,height=1; node *lchild=NULL,*rchild=NULL; node(int _data) {data=_data;} }

qq_44992782的博客 178
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