题目链接:https://vjudge.net/problem/UVA-814
英文题翻译题,模拟题,格式题,好吧,套紫书的题,突然怀疑人生。
#include <set>
#include <map>
#include <cstdio>
#include <vector>
#include <string>
#include <iostream>
using namespace std;
void parse_address(const string& s, string& user, string& mta) {
int k = s.find('@');
user = s.substr(0, k);
mta = s.substr(k+1);
}
int main() {
int k;
string s, t, user1, mta1, user2, mta2;
set<string> addr;
while(cin >> s && s != "*") {
cin >> s >> k;
while(k--) {
cin >> t;
addr.insert(t + "@" + s);
}
}
while(cin >> s && s != "*") {
parse_address(s, user1, mta1);
vector<string> mta;
map<string, vector<string> > dest;
set<string> vis;
while(cin >> t && t != "*") {
parse_address(t, user2, mta2);
if(vis.count(t)) continue;
vis.insert(t);
if(!dest.count(mta2)) {
mta.push_back(mta2);
dest[mta2] = vector<string>();
}
dest[mta2].push_back(t);
}
getline(cin , t);
string data;
while(getline(cin, t) && t[0] != '*')
data += " " + t + "\n";
for(int i = 0; i < mta.size(); i++) {
string mta2 = mta[i];
vector<string> users = dest[mta2];
cout << "Connection between " << mta1 << " and " << mta2<<"\n";
cout << " HELO " << mta1 <<"\n 250\n";
cout << " MAIL FROM:<" << s << ">\n 250\n";
bool ok = false;
for(int i = 0; i < users.size(); i++) {
cout << " RCPT TO:<" << users[i] << ">\n";
if(addr.count(users[i])) {
ok = true;
printf(" 250\n");
}
else printf(" 550\n");
}
if(ok) {
cout<< " DATA\n 354\n" << data << " .\n 250\n";
}
printf(" QUIT\n 221\n");
}
}
return 0;
}