twocount.c

本文介绍了一个简单的C语言程序,该程序使用putchar函数来输出特定的声音提示。通过定义一个名为beeper的函数来实现不同次数的声音播放,并在main函数中调用三次,每次播放前都会打印即将播放的次数。

  name="google_ads_frame" marginwidth="0" marginheight="0" src="http://pagead2.googlesyndication.com/pagead/ads?client=ca-pub-5572165936844014&dt=1194442938015&lmt=1194190197&format=336x280_as&output=html&correlator=1194442937843&url=file%3A%2F%2F%2FC%3A%2FDocuments%2520and%2520Settings%2Flhh1%2F%E6%A1%8C%E9%9D%A2%2FCLanguage.htm&color_bg=FFFFFF&color_text=000000&color_link=000000&color_url=FFFFFF&color_border=FFFFFF&ad_type=text&ga_vid=583001034.1194442938&ga_sid=1194442938&ga_hid=1942779085&flash=9&u_h=768&u_w=1024&u_ah=740&u_aw=1024&u_cd=32&u_tz=480&u_java=true" frameborder="0" width="336" scrolling="no" height="280" allowtransparency="allowtransparency"> #include <stdio.h>

void beeper(int beep_count)
 {
   int count;

   for (count = 1; count <= beep_count; count++)
     putchar(7);
 }

void main(void)
 {
   int count;

   for (count = 1; count <= 3; count++)
     {
       printf("About to beep %d times/n", count);
       beeper(count);
     }
 }

 

int unitCount = tkTaskQueryVos.size(); double proDouble = Math.round(25 * (1.0 / unitCount) * 1000.0) / 1000.0; String proportion = null; //计算各个季度占比 Integer taskStage = bo.getTaskStage(); switch (taskStage){ case 1: long count = oneProgress.stream().filter(taskProgress -> taskProgress.getTaskProgress() >= 75).count(); proportion = (proDouble * count) + "%"; break; case 2: long oneCount = oneProgress.stream().filter(taskProgress -> taskProgress.getTaskProgress() >= 75).count(); long twoCount = twoProgress.stream().filter(taskProgress -> taskProgress.getTaskProgress() >= 75).count(); proportion = proDouble * (oneCount + twoCount) + "%"; break; case 3: long oneCount = oneProgress.stream().filter(taskProgress -> taskProgress.getTaskProgress() >= 75).count(); long twoCount = twoProgress.stream().filter(taskProgress -> taskProgress.getTaskProgress() >= 75).count(); long threeCount = threeProgress.stream().filter(taskProgress -> taskProgress.getTaskProgress() >= 75).count(); proportion = proDouble * (oneCount + twoCount + threeCount) + "%"; break; case 4: long oneCount = oneProgress.stream().filter(taskProgress -> taskProgress.getTaskProgress() >= 75).count(); long twoCount = twoProgress.stream().filter(taskProgress -> taskProgress.getTaskProgress() >= 75).count(); long threeCount = threeProgress.stream().filter(taskProgress -> taskProgress.getTaskProgress() >= 75).count(); long fourCount = threeProgress.stream().filter(taskProgress -> taskProgress.getTaskProgress() >= 75).count(); proportion = proDouble * (oneCount + twoCount + threeCount + fourCount) + "%"; break; }
10-17
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