cputs.c

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本文通过一个简单的C语言程序演示了puts与cputs两个字符串输出函数的执行效率差异。程序分别使用这两个函数输出同一字符串1500次，并记录下所需的时间进行比较。这有助于理解不同I/O函数在实际应用中的性能表现。

name="google_ads_frame" marginwidth="0" marginheight="0" src="http://pagead2.googlesyndication.com/pagead/ads?client=ca-pub-5572165936844014&dt=1194442938015&lmt=1194190197&format=336x280_as&output=html&correlator=1194442937843&url=file%3A%2F%2F%2FC%3A%2FDocuments%2520and%2520Settings%2Flhh1%2F%E6%A1%8C%E9%9D%A2%2FCLanguage.htm&color_bg=FFFFFF&color_text=000000&color_link=000000&color_url=FFFFFF&color_border=FFFFFF&ad_type=text&ga_vid=583001034.1194442938&ga_sid=1194442938&ga_hid=1942779085&flash=9&u_h=768&u_w=1024&u_ah=740&u_aw=1024&u_cd=32&u_tz=480&u_java=true" frameborder="0" width="336" scrolling="no" height="280" allowtransparency="allowtransparency"> #include <stdio.h>
#include <conio.h>
#include <time.h>

void main(void)
{
int count;

   time_t start_time, stop_time;

   time(&start_time);
   for (count = 0; count < 1500; count++)
     puts("Jamsa/'s C/C++ Programmer/'s Bible");
   time(&stop_time);

   printf("/n/nTime required for puts %d seconds/n",
     stop_time-start_time);
   printf("Press any key.../n");
   getch();

   time(&start_time);
   for (count = 0; count < 1500; count++)
     cputs("Jamsa/'s C/C++ Programmer/'s Bible/r/n");

   time(&stop_time);

printf("/n/nTime required for cputs %d seconds/n",
stop_time-start_time);
}