Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.
You may assume no duplicates in the array.
Example 1:
Input: [1,3,5,6], 5 Output: 2
Example 2:
Input: [1,3,5,6], 2 Output: 1
Example 3:
Input: [1,3,5,6], 7 Output: 4
Example 1:
Input: [1,3,5,6], 0 Output: 0
class Solution {
public:
int searchInsert(vector<int>& nums, int target) {
for(int i=0;i<nums.size();i++)
{
if(target>nums[i]&&i!=nums.size()-1)
continue;
else if(target==nums[i])
return i;
else if(target>nums[i]&&i==nums.size()-1)
return i+1;
else
return i;
}
}
};
3374



被折叠的 条评论
为什么被折叠?



