C++EasyX之井字棋

视频链接

井字棋

用EasyX和C++实现井字棋小游戏

源码及注释

#include<graphics.h>

char board_data[3][3] =
{
	{'-','-','-'},
	{'-','-','-'},
	{'-','-','-'},
};

char current_piece = 'O';

//检测指定棋子的玩家是否获胜
bool CheckWin(char c)
{
	// 检查每一行
	for (int i = 0; i < 3; i++)
	{
		if (board_data[i][0] == c && board_data[i][1] == c && board_data[i][2] == c)
			return true;
	}
	// 检查每一列
	for (int j = 0; j < 3; j++)
	{
		if (board_data[0][j] == c && board_data[1][j] == c && board_data[2][j] == c)
			return true;
	}
	// 检查对角线
	if (board_data[0][0] == c && board_data[1][1] == c && board_data[2][2] == c)
		return true;
	if (board_data[0][2] == c && board_data[1][1] == c && board_data[2][0] == c)
		return true;
	// 如果没有匹配，则返回 false
	return