原题回顾
Problem Description
Your task is to calculate the sum of some integers.
Input
Input contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line.
Output
For each group of input integers you should output their sum in one line, and you must note that there is a blank line between outputs.
Sample Input
3
4 1 2 3 4
5 1 2 3 4 5
3 1 2 3
Sample Output
10
15
6
和前面做的主要是注意if_else语句的输出格式,简单题,代码如下:
#include <iostream>
#include<stdlib.h>
using namespace std;
int main()
{
int n,m,*a,sum=0;
cin>>n;
for(int i=1; i<=n; i++)
{
cin>>m;
a=(int*)malloc(m*sizeof(int));
for(int j=0; j<m; j++)
{
cin>>a[j];
sum+=a[j];
}
cout << sum;
if(i!=n)
cout<<endl<<endl;
else
cout<<endl;
sum=0;
}
return 0;
}
本文介绍了如何通过输入一组整数并计算它们的总和,包括输入格式、输出要求及示例代码。代码示例使用C++实现,展示了基本的整数数组操作和循环结构。
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