look following code:
private string FileRenameHandler(string dic ,string filename)
{
DirectoryInfo info = new DirectroyInfo(dic);
int count = info.GetFiles(filename);
if(count != 0)
{
filename = filename.substring(0,filename.lastindexof('.')+"("+count+")"+filename.substring(filename.lastindexof('.'));
FileRenameHandler(dic,filename);
}
return filename;
}
what we can get when we run this code?
it can generate result :
1(1).txt
1(1).txt
why did come to this?
perhaps you have found this bug;
we rename the filename just (count!=0) ;at last the filename we get from inner filerenamehandler can't work;
filename is just the value in the first circly;
we correct it like this;
本文分析了一个文件重命名函数的问题所在,并提供了一种修正方案。原函数试图避免文件名重复,但存在递归调用导致的变量作用域问题,使得文件名无法正确更新。修正后的代码确保了文件名在每次冲突时都能正确地增加编号。
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