PAT (Advanced Level) Practice 1001 A+B Format

本文介绍了一个使用C++编程解决两整数相加并以标准格式输出的问题。输入两个整数a和b,范围在-10^6到10^6之间,程序将计算它们的和,并以逗号分隔每三位数字的标准格式输出结果。此代码片段展示了如何处理大数值的加法和格式化输出。

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Calculate a+b and output the sum in standard format – that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input Specification:

Each input file contains one test case. Each case contains a pair of integers a and b where − 1 0 6 −10^6 106≤a,b≤ 1 0 6 10^6 106. The numbers are separated by a space.

Output Specification:

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input:

-1000000 9

Sample Output:

-999,991

#include <bits/stdc++.h>
using namespace std;

int main() {
    ios::sync_with_stdio(false);
    cin.tie(NULL);
    int a, b;
    cin >> a >> b;
    int c = a + b;
    string ans = "";
    bool flag = false;
    if (c < 0) flag = true;
    c = abs(c);
    int cnt = 0;
    if (c == 0) {
        cout << 0 << "\n";
        return 0;
    }
    while (c){
        if (cnt == 3) {
            cnt = 0;
            ans = "," + ans;
        }
        int x = c % 10;
        c /= 10;
        ans = (char)(x + '0')+ ans;
        cnt++;
    }
    if (flag) ans = "-" + ans;
    cout << ans << '\n';
    return 0;
}

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