【PAT甲级(Advanced Level)练习题】1002. Read Number in Chinese

1. 题目

【牛客网】https://www.nowcoder.com/pat/1/problem/4312

2. c++代码

#include<iostream>
#include<cstring>
#include<cmath>

using namespace std;

/**
 * @author : ACTIM
 * @date : 2020/2/24 01:58
 * @discription : https://www.nowcoder.com/pat/1/problem/4312
 */

int main(){

    string dig[] = {"", "Shi", "Bai", "Qian", "Wan", "Shi", "Bai", "Qian", "Yi"};
    string num[] = {"ling", "yi", "er", "san", "si", "wu", "liu", "qi", "ba", "jiu"};
    string fu = "Fu";

    // 输入
    int m = 0;
    cin>>m;

    // 负
    if(m < 0) {
        cout<<fu<<" ";
        m = -m;
    }

    // 计算位数
    int len = 0;
    int m0 = m;
    while(m0 /= 10){
        len++;
    }

    // 读
    bool zero = false;
    for(int i = len; i >= 0; i--){
        int g = int(m/pow(10.0, i*1.0))%10;
        if(g!=0){
            if(zero){
                cout<<num[0]<<" ";
                zero = false;
            }
            cout<<num[g]<<" "<<dig[i]<<" ";
        }else{
            if(i == 4 && m - m/100000000*100000000 - m%10000 > 0) cout<<dig[i]<<" ";
            else zero = true; // 当千万到万均无数字时不读万，当千万到万存在数字时若千位有数字则不读零
        }
    }

    if(m == 0) cout<<num[0]<<" ";

    return 0;
}