参考自https://www.cnblogs.com/zzy19961112/p/5877436.html#undefined
/*
*dp[i][j]表示时刻i,在车站j,最少还需要等待多长时间
*has_train[t][i][0]表示时刻t,在车站i是否有向右开的火车
*has_train[t][i][1]表示时刻t,在车站i是否有向左开的火车
*/
#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
const int maxn = 55;
const int maxt = 205;
const int INF = 0x3f3f3f3f;
int t[maxn],has_train[maxt][maxn][2],dp[maxt][maxn];
int main()
{
int n,Case = 0;
while (~scanf("%d",&n) && n)
{
int T,M1,M2,d;
memset(has_train,0,sizeof(has_train));
memset(dp,0,sizeof(dp));
scanf("%d",&T);
for (int i = 1;i < n;i++) scanf("%d",&t[i]);
scanf("%d",&M1);
while (M1--)
{
scanf("%d",&d);
for (int j = 1;j < n;j++)
{
if (d <= T) has_train[d][j][0] = 1;
d += t[j];
}
}
scanf("%d",&M2);
while (M2--)
{
scanf("%d",&d);
for (int j = n - 1;j > 0;j--)
{
if (d <= T) has_train[d][j+1][1] = 1;
d += t[j];
}
}
for (int i = 1;i < n;i++) dp[T][i] = INF;
dp[T][n] = 0;
for (int i = T - 1;i >= 0;i--)
{
for (int j =1;j <= n;j++)
{
dp[i][j] = dp[i+1][j] + 1;
if (j < n && has_train[i][j][0] && i + t[j] <= T) dp[i][j] = min(dp[i][j],dp[i+t[j]][j+1]);
if (j > 1 && has_train[i][j][1] && i + t[j-1] <= T) dp[i][j] = min(dp[i][j],dp[i+t[j-1]][j-1]);
}
}
printf("Case Number %d: ",++Case);
dp[0][1]>=INF ? printf("impossible\n"):printf("%d\n",dp[0][1]);
}
return 0;
}