HDU 1076 An Easy Task （水）

An Easy Task

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)

Problem Description

Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?

Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.

Note: if year Y is a leap year, then the 1st leap year is year Y.

 

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains two positive integers Y and N(1<=N<=10000).

 

Output

For each test case, you should output the Nth leap year from year Y.

 

Sample Input

3
2005 25
1855 12
2004 10000

 

Sample Output

2108
1904
43236

Hint
We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0.
 

 

#include <stdio.h>

bool leap(int y){
    return y%4==0&&y%100||y%400==0;
}

int main(){
    int y,T,n,cnt,i;
    scanf("%d",&T);
    while(T--){
        scanf("%d%d",&y,&n);
        cnt=0;
        for(i=y;cnt<n;i++)
            if(leap(i))
                cnt++;
        printf("%d\n",i-1);
    }
    return 0;
}