快乐天使专栏

Given a set of N towns and roads between these towns, the problem is to compute the shortest path allowing a salesman to visit each of the towns once and only once and return to the starting point. 

根据图示规则我们可以发现一下规律:A.如果输入两数x,y两数,满足x==y,且%2为0则为2数之和;B.如果输入两数x,y两数,满足x==y,且%2为1则为2数之和-1;C.如果输入两数x,y两数,满足x-y==2,且%2为0则为2数之和;D.如果输入两数x,y两数,满足x-y==2,且%2为1则为2数之和-1;E.如果输入两数x,y两数,不满足以上ABCD,则输出No

题目要求计算平均数. #includeusing namespace std; int main() { double sum=0.0,a; int n=12; while(n--) {  cin>>a;  sum+=a; } sum=sum/12; cout} http://acm.zju.edu.cn/onlinejudge/showProblem.do

题目需要实现的功能比较简单..给定一个card lengths 值,要求计算出最少的cards数目; In general you can make n cards overhang by 1/2 + 1/3 + 1/4 + ... + 1/(n + 1) card lengths, where the top card overhangs the second by 1/2, the s