字母异位分组

给你一个字符串数组，请你将 字母异位词 组合在一起。可以按任意顺序返回结果列表。

示例 1:

输入: strs = ["eat", "tea", "tan", "ate", "nat", "bat"]

输出: [["bat"],["nat","tan"],["ate","eat","tea"]]

解释：

• 在 strs 中没有字符串可以通过重新排列来形成 "bat"。
• 字符串 "nat" 和 "tan" 是字母异位词，因为它们可以重新排列以形成彼此。
• 字符串 "ate" ，"eat" 和 "tea" 是字母异位词，因为它们可以重新排列以形成彼此。

示例 2:

输入: strs = [""]

输出: [[""]]

示例 3:

输入: strs = ["a"]

输出: [["a"]]

提示：

• 1 <= strs.length <= 104
• 0 <= strs[i].length <= 100
• strs[i] 仅包含小写字母

代码实现

class Solution:
    def groupAnagrams(self, strs: list[str]) -> list[list[str]]:
        groups = {}
        for s in strs:
            key = ''.join(sorted(s))

            if key not in groups:
                groups[key]=[]
            print(s)
            groups[key].append(s)
            print("group[key]: " + str(groups[key]))
            print("group.values: " + str(groups.values()))

        return list(groups.values())

test = Solution()
strs = ["eat", "tea", "tan", "ate", "nat", "bat"]
new_list = test.groupAnagrams(strs)
print(new_list)class Solution:
    def groupAnagrams(self, strs: list[str]) -> list[list[str]]:
        groups = {}
        for s in strs:
            key = ''.join(sorted(s))

            if key not in groups:
                groups[key]=[]
            print(s)
            groups[key].append(s)
            print("group[key]: " + str(groups[key]))
            print("group.values: " + str(groups.values()))

        return list(groups.values())

test = Solution()
strs = ["eat", "tea", "tan", "ate", "nat", "bat"]
new_list = test.groupAnagrams(strs)
print(new_list)