只将以上3个相同的数据成员移相过去。可以设想为:一位学生大学毕业了,留校担任教师,他原有的部分数据对现在的教师身份来说仍然是有用的,应当保留并成为其教师数据的一部分。
没注释的源代码
#include <iostream>
#include<string.h>
using namespace std;
class student
{
public:
student(int,char[],char,float);
int get_num(){return num;}
char *get_name(){return name;}
char get_sex(){return sex;}
void disaply()
{
cout<<"num:"<<num<<endl;
cout<<"name:"<<name<<endl;
cout<<"sex:"<<sex<<endl;
cout<<"score:"<<score<<endl;
}
private:
int num;
char name[20];
char sex;
float score;
};
student::student(int n,char nam[],char s,float sco)
{
num=n;
strcpy(name,nam);
sex=s;
score=sco;
}
class teacher
{
public:
teacher(){}
teacher(student&);
teacher(int n,char nam[],char sex,float pay);
void display();
private:
int num;
char name[20];
char sex;
float pay;
};
teacher::teacher(int n,char nam[],char s,float p)
{
num=n;
strcpy(name,nam);
sex=s;
pay=p;
}
teacher::teacher(student&stud)
{
num=stud.get_num();
strcpy(name,stud.get_name());
sex=stud.get_sex();
pay=1500;
}
void teacher::display()
{
cout<<"num:"<<num<<endl;
cout<<"name:"<<name<<endl;
cout<<"sex:"<<sex<<endl;
cout<<"pay:"<<pay<<endl;
}
int main()
{
teacher teacher1(1001,"li",'f',1234.5),teacher2;
student student1(1002,"zhang",'m',89.5);
cout<<"student1:"<<endl;
student1.disaply();
teacher2=teacher(student1);
cout<<"teacher2:"<<endl;
teacher2.display();
return 0;
}